Let О”abcв€јо”def And Their Areas Be Respectively 64cmві And 121cmві. If Ef=15.4cm Find Bc. 〈REAL · 2024〉

Area(△ABC)Area(△DEF)=(BCEF)2the fraction with numerator Area open paren triangle cap A cap B cap C close paren and denominator Area open paren triangle cap D cap E cap F close paren end-fraction equals open paren the fraction with numerator cap B cap C and denominator cap E cap F end-fraction close paren squared 2. Substitute the known values Plug the given areas ( ) and the length of side EFcap E cap F ) into the formula:

The length of side BCcap B cap C 1. Identify the relationship between areas and sides Solve for side BCcap B cap C Multiply

Take the square root of both sides of the equation to find the ratio of the corresponding side lengths: Solve for side BCcap B cap C Multiply

811=BC15.48 over 11 end-fraction equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction 4. Solve for side BCcap B cap C Multiply both sides by to isolate BCcap B cap C Solve for side BCcap B cap C Multiply