: word[:index] takes everything before the letter, and word[index + len(letter):] takes everything after it. Adding them together effectively "deletes" the unwanted part.
The prompt likely refers to from the CodeHS Python curriculum. This exercise requires you to write a function that removes every instance of a specific "letter" (or substring) from a given word. Correct Python Implementation
: This method returns the starting index of the first occurrence of letter . If it isn't found, it returns -1 .
: The while True ensures the code keeps searching until every instance is gone, which is necessary if the letter appears multiple times (e.g., removing "na" from "banana"). Alternative (Standard Python)
: If letter is an empty string, the loop would run forever; we return the original word immediately.
While the CodeHS exercise often requires the manual loop approach above, the simplest way to do this in standard Python is using the .replace() method:
def remove_all_from_string(word, letter): # If the letter to remove is empty, return the original word if letter == "": return word while True: # Find the first occurrence of the letter index = word.find(letter) # If .find() returns -1, the letter is no longer in the string if index == -1: return word # Rebuild the string by skipping the found instance word = word[:index] + word[index + len(letter):] # Example usage: # word = input("Enter word: ") # letter = input("Enter letter to remove: ") # print(remove_all_from_string(word, letter)) Use code with caution. Copied to clipboard Breakdown of the Code
: word[:index] takes everything before the letter, and word[index + len(letter):] takes everything after it. Adding them together effectively "deletes" the unwanted part.
The prompt likely refers to from the CodeHS Python curriculum. This exercise requires you to write a function that removes every instance of a specific "letter" (or substring) from a given word. Correct Python Implementation 7.6 / 10 123...
: This method returns the starting index of the first occurrence of letter . If it isn't found, it returns -1 . : word[:index] takes everything before the letter, and
: The while True ensures the code keeps searching until every instance is gone, which is necessary if the letter appears multiple times (e.g., removing "na" from "banana"). Alternative (Standard Python) This exercise requires you to write a function
: If letter is an empty string, the loop would run forever; we return the original word immediately.
While the CodeHS exercise often requires the manual loop approach above, the simplest way to do this in standard Python is using the .replace() method:
def remove_all_from_string(word, letter): # If the letter to remove is empty, return the original word if letter == "": return word while True: # Find the first occurrence of the letter index = word.find(letter) # If .find() returns -1, the letter is no longer in the string if index == -1: return word # Rebuild the string by skipping the found instance word = word[:index] + word[index + len(letter):] # Example usage: # word = input("Enter word: ") # letter = input("Enter letter to remove: ") # print(remove_all_from_string(word, letter)) Use code with caution. Copied to clipboard Breakdown of the Code